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11. Rezolvaţi prin metoda reducerii sistemele:
(3(x+2y)-2(2x+y-3)+5=21
5(x-y+1)=4(x+y+2)-23
a)
c)
d)
[3(x+y+3)+2(x-y-4)=x+3y+3
2(x-y-2)-3(x+y+3)=-30
[3(x+7)=4(y+3)
b)
[2(-x-y+3)-4(x-y+1)+8=32
[2(x+y+4)=3(2x+2y-3)+21
; d) [4(x+y+1)= 5(2x+y+ 2) +9
(2(-x+y-3)+3(x-y+2)=1