Răspuns:
a)7(x+y-z)
b)2(a+b+c-d)
c)x(x+1)
d)2x(2x^3-x+4)
e))(x+1)(3-2y)
f)(y-1)(6y+3)
h)(x+3)^2
i)2(x-1)^2
j)(x-10)(x+10)
l)(x+1-2)(x+1+2)=(x-1)(x+3)=(x^2+3x-x-3)=(x^2+2x-3)
m)(3-x+2)(3-x-2)=(5-x)(1-x)=(5-5x-x+x^2)=(5-6x+x^2)=(x^2-6x+5)
Explicație pas cu pas:
