Răspuns:
Explicație:
160 g sol. HCl , c=10%
react. cu Ca(OH)2
g,moli Ca(OH)2
-se afla md sol. de HCl
md= c .ms : 100
md= 10 . 160 : 100 = 16g HCl
16g xg
2HCl + Ca(OH)2 = CaCl2 + 2H2O
2.36,5g 74g
x= 16 . 74 : 73 = 16,22 g Ca(OH)2
n= m : M
MCa(OH)2= 40 + 2 + 2.16=74----> 74g/moli
n= 16,22g : 74g/moli= 0,22moli Ca(OH)2