Răspuns:
[tex]\bigg\{-\dfrac{1}{2} - \dfrac{\sqrt{3} }{2}i;-\dfrac{1}{2} + \dfrac{\sqrt{3} }{2}i\bigg\}[/tex]
Explicație pas cu pas:
[tex]x^2 + x + 1 = 0[/tex]
[tex]\Delta = 1^2 - 4\cdot1\cdot1 = 1-4 = -3[/tex]
[tex]x_1 = \dfrac{-1-\sqrt{-3} }{2} = \dfrac{-1-i\sqrt{3} }{2} = -\dfrac{1}{2} - \dfrac{\sqrt{3} }{2}i\\[/tex]
[tex]x_2 = \dfrac{-1+\sqrt{-3} }{2} = \dfrac{-1+i\sqrt{3} }{2} = -\dfrac{1}{2} + \dfrac{\sqrt{3} }{2}i[/tex]
