Răspuns:
A,Fe= 56g/mol
miu,FeCl2= 127g/mol
miu,NaOH=40g/mol
miu,Na2SO4= 142g/mol
56g,.....................127g
Fe + 2HCl---> FeCl2 + H2
5,6g.......................x x=m= 12,7g FeCl2
2x40g....................................142g
2NaOH + H2SO4-----> Na2SO4 + 2H2O
4g.............................................x x= m= 7,1g Na2SO4
Explicație: