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{495:[30:(6×4-9×a)]+339:3-124:4)-25×6=31​
unde este 124:4 este acolada ca la început dar nu am mai știut cum se pune
rpd e urgent


Răspuns :

Răspuns:

{495:[30:(6×4-9×a)]+339:3-124:4}-150=31​

[tex]495:[30:(24-9a)]+113-31=31+150[/tex]

[tex]495:[30:(24-9a)]+113=181+31\\\\495:[30:(24-9a)]=212-113\\\\30:(24-9a)=495:99\\\\24-9a=30:5\\\\9a=24-6\\\\ a=18:9\\\\ a=2[/tex]

Răspuns: [tex]\bf \red{\underline{a=2}}[/tex]

Explicație pas cu pas:

Vom folosi metoda mersului invers pentru rezolvarea exercițiului

[tex]\bf \bigg\{ 495:\Big[30:\big(6\cdot 4-9\cdot a\big) \Big]+339:3-124:4\bigg\} -25\cdot6=31[/tex]

[tex]\bf \bigg\{ 495:\Big[30:\big(24-9\cdot a\big) \Big]+339:3-124:4\bigg\} -25\cdot6=31[/tex]

[tex]\bf \bigg\{ 495:\Big[30:\big(24-9\cdot a\big) \Big]+113-31\bigg\} -25\cdot6=31[/tex]

[tex]\bf \bigg\{ 495:\Big[30:\big(24-9\cdot a\big) \Big]+113-31\bigg\} -150=31[/tex]

[tex]\bf \bigg\{ 495:\Big[30:\big(24-9\cdot a\big) \Big]+113-31\bigg\} =31+150[/tex]

[tex]\bf 495:\Big[30:\big(24-9\cdot a\big) \Big]+113-31 =181[/tex]

[tex]\bf 495:\Big[30:\big(24-9\cdot a\big) \Big]+113 =181+31[/tex]

[tex]\bf 495:\Big[30:\big(24-9\cdot a\big) \Big]+113 =212[/tex]

[tex]\bf 495:\Big[30:\big(24-9\cdot a\big) \Big] =212-113[/tex]

[tex]\bf 495:\Big[30:\big(24-9\cdot a\big) \Big] =99[/tex]

[tex]\bf 495=99 \cdot\Big[30:\big(24-9\cdot a\big) \Big][/tex]

[tex]\bf 495:99=\Big[30:\big(24-9\cdot a\big) \Big][/tex]

[tex]\bf 5=30:\Big(24-9\cdot a\Big)[/tex]

[tex]\bf 5\cdot\Big(24-9\cdot a\Big) = 30[/tex]

[tex]\bf \Big(24-9\cdot a\Big) = 30:5[/tex]

[tex]\bf 24-9\cdot a = 6[/tex]

[tex]\bf 24=6+9\cdot a[/tex]

[tex]\bf 24-6=9\cdot a[/tex]

[tex]\bf 18=9\cdot a[/tex]

[tex]\bf a= 18 : 9[/tex]

[tex]\bf \red{\underline{a=2}}[/tex]

==pav38==

Baftă multă !