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cine ma poate ajuta va rog​

Cine Ma Poate Ajuta Va Rog class=

Răspuns :

Răspuns:

[tex]3/48+a=23/24\\\\a=23/24-3/48\\\\a=\frac{23*2-3}{48} = > a=43/48\\\\\\\\77/144-a=5/12\\\\a=77/144-5/12\\\\a=\frac{77-5*12}{144} = > a=17/144\\\\\\\\8/11-39/143=\frac{8*13-39}{143} =65/143[/tex]

Răspuns:

[tex]\boldsymbol{a) \ \red{ \dfrac{43}{48} }}, \ \boldsymbol{b) \ \red{ \dfrac{17}{144} }}, \ \boldsymbol{c) \ \red{ \dfrac{65}{143} }}[/tex]

Explicație pas cu pas:

a) Aflăm prin scădere

[tex]\dfrac{^{2)} 23}{24} - \dfrac{3}{48} = \dfrac{46}{48} - \dfrac{3}{48} = \dfrac{46-3}{48} = \dfrac{43}{48}[/tex]

Proba:

[tex]\dfrac{3}{48} + \dfrac{43}{48} = \dfrac{46}{48}^{(2} = \dfrac{23}{24}[/tex]

b) Aflăm prin scădere

[tex]\dfrac{77}{144} - \dfrac{^{12)} 5}{12} = \dfrac{77}{144} - \dfrac{60}{144} = \dfrac{77-60}{144} = \dfrac{17}{144}[/tex]

Proba:

[tex]\dfrac{77}{144} - \dfrac{17}{144} = \dfrac{60}{144}^{(12} = \dfrac{5}{12}[/tex]

c) Aflăm prin scădere

[tex]\dfrac{^{13)} 8}{11} - \dfrac{39}{143} = \dfrac{104}{143} - \dfrac{39}{143} = \dfrac{104-39}{143} = \dfrac{65}{143}[/tex]

Proba:

[tex]\dfrac{39}{143} + \dfrac{65}{143} = \dfrac{104}{143}^{(13} = \dfrac{8}{11}[/tex]