Răspuns:
[tex](b \div 2 + 5) + b + ((b \div 2 + 5) \div 4 - 2) = 59 \\ ( \frac{b}{2} + 5) + b + (( \frac{b}{2} + 5) \times \frac{1}{4} - 2) = 59 \\ \frac{b + 10}{2} + b + ( \frac{b + 10}{2} \times \frac{1}{4} - 2) = 59 \\ \frac{b + 10 + 2b}{2} + \frac{b + 10 - 16}{8} = 59 \\ 4(3b + 10) + b - 6 = 472 \\ 12b + 10 + b = 472 + 6 \\ 13b = 478 - 10 \\ 13b = 468 \\ b = \frac{468}{13} \\ b = 36[/tex]
