[tex]\it Not\breve am\ numerele\ cu\ a\ \d si\ b\ .\\ \\ 0,2=\dfrac{\ \ 2^{(2}}{10}=\dfrac{1}{5};\ \ \ \ 0,5=\dfrac{\ 5^{(5}}{10}=\dfrac{1}{2}\\ \\ \\ \{a,\ b\}\ i.\ p.\ \bigg\{\dfrac{1}{5},\ \dfrac{1}{2}\bigg\} \Rightarrow \{a,\ b\}\ d.\ p.\ \{5,\ 2\} \Rightarrow \dfrac{a}{5}=\dfrac{b}{2} \Rightarrow b=\dfrac{2a}{5}\ \ \ \ \ \ (1)\\ \\ \\ 2a+b=24 \Rightarrow b=24-2a\ \ \ \ (2)[/tex]
[tex]\it (1),\ (2) \Rightarrow \dfrac{2a}{5}=24-2a\bigg|_{\cdot5} \Rightarrow 2a=120-10a\bigg|_{+10a} \Rightarrow 12a=120 \Rightarrow a=10\\ \\ \\ b=24-2a=24-20=4[/tex]
