Răspuns:
[tex]1. \: a)a = 3 \\ b = 2 \\ b)a = - 1 \\ b = 6 \\ c)a = - 4 \\ b = 0 \\ d)a = 0 \\ b = - 1[/tex]
[tex]2. \: g(x) = 3x - 1 \\ g( - 1) = - 3 + 1 = - 2 \\ g(0) = 0 - 1 = - 1 \\ g( \frac{1}{3} ) = 1 - 1 = 0 \\ g( \frac{1}{ \sqrt{3} } ) = \frac{3}{ \sqrt{3} } - 1 = \frac{3 \sqrt{3} }{3} - 1 = \sqrt{3} - 1[/tex]
[tex]3. \: a) \: h( - 2) = 0 = > \\ = > - 2 + 2 = 0 \\ 0 = 0 \\ h(1) = 1 \\ - 1 + 2 = 1 \\ 1 = 1[/tex]
si la 3 la a) scrii => A(-2;0) si B(1;1) € Gf
