Răspuns:
[tex]\frac{x+1}{x-2} -pentru:x=0\\\\\frac{0+1}{0-2} =-\frac{1}{2} \\\\pentru:x=-1\\\\\frac{-1+1}{-1-2} =0\\\\\\\\\frac{y^2+y+1}{y^3-1} -pentru:y=2\\\\\frac{2^2+2+1}{2^3-1} =\frac{7}{7} =1\\\\-pentru:y=-1\\\\\frac{(-1)^2+(-1)+1}{(-1)^3-1}=-\frac{1}{2} \\\\\\\\\frac{z^2-6z-9}{z^2+4z-4} -pentru:z=1\\\\\frac{1^2-6*1-9}{1^2+4*1-4} =-\frac{14}{1} =-14\\\\pentru:z=-2\\\\\frac{(-2)^2-6*(-2)-9}{(-2)^2+4*(-2)-4} =-\frac{7}{8}[/tex]
