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25 află numărul natural x din inegal are a x + 2,5 < 7,25 b x 3,21 mai mai mic decât 4,57 d 3,2 + 2,7 mai mare decât x 0,9​

Răspuns :

Răspuns:

[tex]a.)x+2,5 < 7,25= > x < 7,25-2,5= > x < 4,75\\\\\\b.)3,21x < 4,57= > x < 4,57:3,21= > x < 1,423\\\\\\c.)3,2+2,7 > 0,9x= > x < 5,9:0,9= > x < 6,(5)[/tex]

[tex]\it a)\ \ x+2,5 < 7,25\bigg|_{-2,5} \Rightarrow x < 4,75 \Rightarrow x\in\{0,\ 1,\ 2,\ 3,\ 4\}\\ \\ \\ b)\ \ 3,21x < 4,75\bigg|_{\cdot100} \Rightarrow 321x < 475 \stackrel{x\in\mathbb N}{\Longrightarrow}\ x\in\{0,\ 1\}[/tex]