Răspuns:
30a < 15a ---> 45a.....moli
r1: 2CH4-------> C2H2+ 3H2
7,5 a < 15a
CH4---------> C + 2H2
25a 25a
CH4------------------->CH4
daca in 100a moli amestec am 15a moli acetilena ,voi avea 45a moli H2 si (60a-45a) moli H2 si (100a-15a-45a-15a) moli metan netransformat
total moli CH4= V/Vm= 2000/22,4kmol=89,2857kmol
89,2857=(30+7,5+25)a---> a=1,4285kmol
niu,C2H2=15a=15x1,4285 kmol=21,43 kmol
V=niuxVm= 21,43kmolx22,4 m³/kmol=480m³
62,5 kmolCH4.......30kmol r1..........25kmol netransformat
100kmol...........x.....................................y
x=48%
y=40%
Explicație: