Răspuns:
Explicație pas cu pas:
10. Calculați, folosind regulile de calcul cu puteri: a) [2/7]^5 × [2/7]^11 × [2/7]^28
b) ([1/3)^2]^7 : (1/3)^12
c) [(3/5)^4]^6 × (3/5)^8 : (3/5)^2^5
a) (2/7)⁵ × (2/7)¹¹ × (2/7)²⁸=(2/7)⁽⁵⁺¹¹⁺²⁸⁾=(2/7)⁴⁴
b) [(1/3)²]⁷ : (1/3)¹²=(1/3)⁽²ˣ⁷⁾: (1/3)¹²=(1/3)¹⁴: (1/3)¹²=(1/3)⁽¹⁴⁻¹²⁾=(1/3)²=1/9
c) 2⁵=32
[(3/5))⁴]⁶ × (3/5)⁸ : (3/5)³²=(3/5)⁽⁴ˣ⁶⁾× (3/5)⁸ : (3/5)³²=
(3/5)²⁴× (3/5)⁸ : (3/5)³²=(3/5)⁽²⁴⁺⁸⁾ : (3/5)³²=(3/5)³² : (3/5)³²=
(3/5)⁽³²⁻³²⁾=(3/5)⁰=1
d) [(5/11)³]¹⁵×(5/11)²⁰:(5/11)⁶⁵=(5/11)⁽³ˣ¹⁵⁾×(5/11)²⁰:(5/11)⁶⁵=(5/11)⁴⁵×(5/11)²⁰:(5/11)⁶⁵=
(5/11)⁽⁴⁵⁺²⁰⁾:(5/11)⁶⁵=(5/11)⁶⁵:(5/11)⁶⁵=(5/11)⁽⁶⁵⁻⁶⁵⁾=(5/11)⁰=1
