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5. Rezolvați prin metoda substituției sistemele: (2x+y=0 4x-2y=0 a) x-3y=7' b) (2x+3y=-3 ; c) (2x-y=-1 x-y=-1 d) (-x+2y=5 (3x-2y=0' (2x+y=-7 x-2y=-8 e) (3x-4y=-5' f) (3x-4y=-15 4x-5y=23 3x+4y=-4' g) ; h) 2x-y=-5 3x-y=9​.Va rog!!