Răspuns:
[tex](g) = \dfrac{1}{8} : \dfrac{1}{4} + \dfrac{1}{4} - \dfrac{25}{100}^{(25} : 2 = \dfrac{1}{8} \cdot \dfrac{4}{1} + \dfrac{1}{4} - \dfrac{1}{4} \cdot \dfrac{1}{2} = \dfrac{^{4)} 1}{2} + \dfrac{^{2)}1}{4} - \dfrac{1}{8} = \dfrac{4 + 2 - 1}{8} = \dfrac{5}{8}[/tex]
[tex](h) = \dfrac{\not6}{7} \cdot \dfrac{6}{\not9} : \dfrac{8}{7} = \dfrac{2}{\not7} \cdot \dfrac{\not6}{\not3} \cdot \dfrac{\not7}{8} = \dfrac{2}{1} \cdot \dfrac{2}{1} \cdot \dfrac{1}{8} = \dfrac{1}{2}[/tex]
