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Propunere de rezolvare
2LiOH(400 grade C)->Li2O + H2O
2 moli LiOH.....................1 mol Li2O
2 moli LiOH......produc 1 mol Li2O
8 moli Li2O.......produc x moli Li2O
x moli Li2O =8 moli.1/2=4 moli
m(g)=masa Li2O= n moli .M Li2O( g/ mol)
M Li2O=2.A Li + A O=2.6+16=28 g/ mol
m (g) Li2O=4 moli.28g/ mol= 112 g
R:112 g Li2O