CnH2n+1-NH2 = monoaminelor alifatice saturate
100% amina ................ 16,09% N
miu.amina .................... 14 g N
=> miu = 87 g/mol
=> 14n + 17 = 87
=> n = 5
=> C5H11NH2
C-C-C-C-C-NH2 = NU
C-C-C-CH(CH3)-NH2 = DA x1 pereche
C-C-C-CH(NH2)-C= DA x1 pereche
C-C(CH3)-CH(NH2)-C = DA x1 pereche
C-C-CH(NH2)-C-C = DA x1 pereche
C-C-C-C-NH-C = NU
C-C-CH(CH3)-NH-C = DA x1 pereche
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