1.1 rezolva cu ajutorul notitelor sau a manualului
3.3 mC:mH= 92,3:(100-92,3)
nC:nH= 92,3/12 : 7,7/1
= 7,69:7,7
= 1:1-----------> C2H2(ACETILENA)
CH≡CH+ 2H2---> CH3-CH3
+Br2---> CHBr=CHBr + Br2----> CHBr2-CHBr2
+HBr---> CH2=CHBr
+HOH---> [CH2=CHOH]⇄CH2-HC=O
+5/2O2----> 2CO2+H2O
2CH4---> C2H2+3H2
CH≡CH+ 2Na------> CNa≡CNa+H2
CH≡CH+........---> CAg≡CAg=....................completeaza
