Răspuns
Formule
logₐx=1/logₓb x>0 x=/=1
log₂x+logₓ2=2
log₂x+1/log₂x=2
Substitutie log₂x=y
y+1/y=2
y-2+1/y=0
y²-2y+1=0
(y-1)²=0
y-1=0
y=1
Revii la necunoscuta x
log₂x=1
x=2¹=2
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lg10⁴+lg10³+2lg10²+3lg10=?
4lg10+3lg10+2*2lg 10+3=
4+3+4+3=14
Explicație pas cu pas:
