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(y+5 )la a doua
(3y+4x) la a doua
(3x-5y) la a doua
(2a+3b) ) la a doua
(4x-1) 2 la a doua
(X+1) la a doua
( x-7y) la a doua
(×+2)(×-2)
(2×+3y)(2x-3y)
(3×-7)(3x+7)
(4x+5) (4x-5)
(y-5)(y+5)
(x-3y)(x+3y)


Răspuns :

Reguli de calcul cu puteri prescurtat:
(a+b)^2 = a^2 + 2 × a × b + b^2
(a-b)^2= a^2-2×a×b+b^2
(a-b)(a+b)= a^2 - b^2
Invata astea si aplica-le pe exercitiu iti dau un exemplu:
(y+5)^2 = y^2+2×y×5+5^2 =y^2+10y+10
Baftă!