(x; y; z) i.p (0,5; 0,(3); 0,25)
x + y + z = 36
0,5x = 0,(3)y = 0,25z
5x/10 = 3y/9 = 25z/100
simplificam fiecare fractie corespunzator
x/2 = y/3 = z/4 = k
=> x = 2k
=> y = 3k
=> z = 4k
2k + 3k + 4k = 36
9k = 36 | : 9
k = 4
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Aşadar avem :
x = 2k = 2×4 = 8
y = 3k = 3 × 4 = 12
z = 4k = 4 × 4 = 16