prima zi : a=b/3
a doua zi : b
a treia zi: c=(a+b):2
a+b+c=48
b/3+b+(b/3+b):2=48
b/3+b+b/6+b/2=48; n.c.=6
2b+6b+b+3b=48x6
12b=288
b=288:12
b=24
a=24:3=8
8+24+c=48
c=48-32
c=16
Deci:
a=8 km a parcurs in prima zi
b=24 km a parcurs a doua zi
c=16 km a parcurs a treia zi