1) 3x+4xy= x(3+4y)
2)(x+1)•x+3•(x+1)=(x+1)(x+3)
3) 3√2x-2√2x^2+4√2x^3-5√2x^4=
=√2x(3-2x+4x^2-2x+3)=
=√2x(-5x^3+4x^2-2x+3)=
=√2x(-5x^3+5x^2-x^2+x-3x+3)=
=√2x[-5x^2(x-1)-x(x-1)-3(x-1)]=
=√2x[(x-1)(-5x^2-x-3)]=
= - √2x(x-1)(5x^2+x+3)
4) a=32 și ab+ac=800, afl-ați b+c.
ab+ac=800
a(b+c)=800
32(b+c)=800
b+c=800÷32
b+c=25
