cum se rezolva asta pls?
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Răspuns:
Explicație pas cu pas:
[tex]2^{-1}+\dfrac{1}{3}:6^{-1}+\left(\dfrac{1}{2}\right)^0\cdot\dfrac{1}{2}=\\\dfrac{1}{2}+\dfrac{1}{3}:\dfrac{1}{6}+1\cdot \dfrac{1}{2}=\\\dfrac{1}{2}+\dfrac{1}{3}\cdot 6+\dfrac{1}{2}=\\1+2=3\\\texttt{Raspunsul este C)}[/tex]
2^-1 +1/3 :6^-1+(1/2)^0 ×1/2=
=1/2 +1/3×6^1+1×1/2=
=1/2+1/3×6/1+1/1×1/2=
=1/2 + 1×2 totul supra/1×1 +1×1 totul supra /1×2=
=1/2 + 2/1 +1/2=
=1+2×2+1 tot asta supra/2=
=1+4+1 tot asta supra/2=
=6/2 simplicat cu 2=
=3/1 =
=3
Raspunsul corect este C) 3