7/.
PV = nRT
n = V/Vm, VM = volumul molar
= 350/22,4 = 15,625 moli O2
=> P = nRT/V = 15,625x0,082x(273+20)/10
= 37,5 atm
8/.
a moli b moli 360 g
2H2 + O2 => 2H2O
2 1 2x18
=> a = 2x360/2x18 = 20 moli O2
=> b = 1x360/2x18 = 10 moli H2
amandoua calculate in conditii normale .... dar ce volum vor ocupa in conditiile date in probelma...??
pt. H2:
PV = nRT => V = nRT/P
= 10x0,082x(273+127)/2
= 164 L H2
pt O2:
PV = nRT => V = nRT/P
= 20x0,082x(273+127)/2
= 328 L O2
