buna
[tex] \sqrt{x + 3} = 3 \\ x + 3 = 9 \\ x = 9 - 3 \\ x = 6 \\ verfic \: \: daca \: valoare \:este \: buna \: \: \sqrt{6 + 3} = 3 \\ 3 = 3 \\ x = 6[/tex]
[tex] \sqrt{2x + 1} = x - 1 \\ 2x + 1 = x {}^{2} - 2x + 1 \\ 2x = x {}^{2} - 2x \\ 2x - x {}^{2} + 2x = 0 \\ 4x - x {}^{2} = 0 \\ x(4 - x) = 0 \\ x = 0 \\ 4 - x = 0 \\ x = 0 \\ x = 4 \\ verificare \sqrt{2 \times 0 + 1} = 0 - 1 \\ \sqrt{2 \times 4 + 1} = 4 - 1 \\ 1 = - 1 \\ 3 = 3 \\ x = 4[/tex]
sper ca te am ajutat !
