CH4
M=12+4=16------> 16g/moli
1mol CH4------------6,023.10²³ molecule CH4
Xmoli----------------24,088.10²³ molecule CH4
x=24,088 .10²³ : 6,023.10²³ =3,99 moli CH4
m= n.m
m=3,99 moli . 16g/moli=63, 9 g CH4
SAU
1mol CH4--------16g----------6,023.10²³ molecule CH4
xg------------24,088 .10²³
x=16. 24,088.10²³ : 6,023 .10²³=63,9 g CH4