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Se dizolva 112g koh in 500 g h2o . prin firebere se pierde 120g de apa si apoi se adauga 28g koh . sa se calculeze concentratia procentuala a solutiei finale, va rog URGENT

Răspuns :

md,i= 112g

ms,i= md+m,apa= 612g

md,final= mdi+m,adaugat=112+28=>140gKOH

ms,f= msi-m,apa+m,adaugat=612-120+28=>520g

c=mdx100/ms= 140x100/520=........................calculeaza !!!!!