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Determinați numerele naturale consecutive a, b,c stiind ca a+b+c=312


Răspuns :

a + b + c = 312

b = a + 1

c = a + 2

a + a + 1 + a + 2 = 312

3 × a + 1 + 2 = 312

3 × a + 1 = 312 - 2

3 × a + 1 = 310

3 × a = 310 - 1

3 × a = 309

a = 309 : 3

a = 103

b = 103 + 1

b = 104

c = 103 + 2

c = 105