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Rezolvati ecuatia log in baza 2(x la a2a+3)=5,x apartine R

Răspuns :

log in baza 2(x²+3)=5;  x∈ R

x²+3>0

log in baza 2(x²+3)= log in baza 2(2^5)

=> x²+3=32

x²=29

=> x1=+√29 si x2=-√29