Răspuns:
Explicație pas cu pas:
→ introduc intregii in fractie
2 intregi si 1 / 3 = ( 2 x 3 + 1) / 3 = 7 / 3
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( 7 / 3) × ( 4 / 7 ) + 9/5 : 3 - 1 /12 =
= 4/3 + 9/5 × 1 / 3 - 1/12 =
= 4/3 + 3/5 - 1/12 = → cmmmc al numitorilor 3; 5 si 12 = 60
= ( 4 ×20) /(3×20) + (3×12)/(5×12) - 5/(12×5) =
= 80/60 + 36/60 - 5/60 =
= ( 116 - 5) / 60 =
= 111/60 =
= 1 intreg si 51/60
