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4×(√3+1) la puterea 2-√3×(8-√3)-(√21-√2)×(√21+√2)​

Răspuns :

4(√3+1)^2-√3(8-√3)-(√21-√2)(√21+√2)=

4(3+2√3+1)-(8√3-3)-(√21^2-√2^2)=

12+8√3+4-8√3+3-21+2=

12+4+3-21+2=

16+3-21+2=

19-21+2=

-2+2=0