CaCO3 = CaO + CO2
CaO + H2O= Ca(OH)2
-se afla masa de calcar pura [ mp ]
p=mp.100 : mt p=puritatea
mp=p.mt : 100
mp=2000 . 90 :100=1800 kg CaCO3 pur
-se afla masa de CaO din prima ec.
1800kg xkg
CaCO3=CaO + CO2
100kg 56kg
x=1800.56 :100=1008 kg CaO
-se afla masa de Ca(OH)2 obtinuta in a doua ec.
1008 kg ykg
CaO + H2O=Ca(OH)2
56kg 74kg
y=1008 . 74 : 56=1332 kg Ca(OH)2
MCaO=40+16=56----->56kg/kmoli
MCaCO3=40 +12 +3.16=100------>100kg/kmoli
MCa(OH)2= 40+2.16 +2=74------>74kg/kmoli