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Cine ma poate ajuta?
Multumesc!!!

3(2x+9)<15
4(5x+8)>12
5(3x+8)> sau =10
7(1-2x) 5(3-4x)>-25
6(7-5x)<-48


Răspuns :

A)

[tex]3(2x + 9) < 15 \\ 6x + 27 < 15 \\ 6x < 15 - 27 \\ 6x < - 12 \\ x < - 12 \div 6 \\ x < - 2[/tex]

x={ ...,-6,-5,-4,-3}

B)

[tex]4(5x + 8) > 12 \\ 20x + 32 > 12 \\ 20x > 12 - 32 \\ 20x > - 20 \\ x > 20 \div 20 \\ x > 1[/tex]

x={2,3,4,5,...}

C)

[tex]5(3x + 8) \geqslant 10 \\ 15x + 40 \geqslant 10 \\ 15x \geqslant 10 - 40 \\ 15x \geqslant - 30 \\ x \geqslant - 30 \div 15 \\ x \geqslant - 2 [/tex]

x={-2,-1,0,1,2,...}

D)

[tex]7(1 - 2x) + 5(3 - 4x) > - 25 \\ 7 - 14x + 15 - 20x > - 25 \\ - 34x + 22 > - 25 \\ - 34x > - 25 - 22 \\ - 34x > - 47 = > \\ = > x \: nu \: are \: solutie \: in \\ multimea \: numerelor \: intregi[/tex]

E)

[tex]6(7 - 5x) < - 48 \\ 42 - 30x < - 48 \\ - 30x < - 48 - 42 \\ - 30x < - 90 \\ x < - 90 \div ( - 30) \\ x < 3[/tex]

x={...,-2,-1,0,1,2}