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Rezolvati multimea numerelor reale cu ecuatiile :
A) 2x+1 / 3x-2 = 2x +5 / 3x+1

B) { 5 ( x+y) -2y =5
{ 3x-2(x-y) =1
{


Răspuns :

[tex]a) \frac{2x + 1}{3x - 2} = \frac{2x + 5}{3x + 1} = > (2x + 1) \times (3x + 1) = (2x + 5) \times (3x + 2) = > 6x {}^{2} + 2x + 3x + 1 = 6x {}^{2} - 4x + 15x - 10 = > 2x + 3x + 1 = - 4x + 15x - 10 = > 5x + 1 = 11x - 10 = > 5x - 11x = - 10 - 1 = > - 6x = - 11 = > x = \frac{11}{6} .[/tex]