Răspuns:
a)√2²-2√2x+x²=2-2√2x+x²
b)a²-2a×2√3+(2√3)²=a²-4√3a+12
c)(1/2)²-2×1/2x+x²=1/4-x+x²
d)(1/3x)²-2×1/3x×1/4y+(1/4y)²=1/9x²-1/6xy+1/16y²
e)(2√2x)²-2×2√2x×3√3y+(3√3y)²=4×2x-12√6xy+9×3y=8x-12√6xy+27y
f)(x²)²-2x²×3b²+(3b²)²=x la a 4 - 6b²x²+9b la a 4
g)(1/√2x-4/3)²=(3-4√2x/3√2x)²=(3-4√2x)²/9×2x=9-24√2x+32x/18x
Explicație pas cu pas: