2N2O => produsi
=> r. de ordin II
k= Ae^(-Ea/RT), unde Ea= 50000 cal---> R = 2 cal/molkelvin\
T = 273 + 895 = 1168 K
prin logaritmare:
lnk1 = lnA - Ea/RT1
lnk2 = lnA - Ea/RT2
lnK2/lnK1 = Ea(1/T2 - 1/T1)
lnK2/lnK1 = 50000(1/1000 - 1/1168)
lnK2/lnK1 = 7,2
=> lnk2 = 7,2xlnk1
= -0,145
=> k2 = e^-0,145 = 2,72^-0,145
K2 = 0,865 l*mol^-1*s^-1