Calculati integrala:
Am nevoie de o indicatie.
Multumesc mult!!
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Răspuns:
Explicație pas cu pas:
[tex]u=x^{\frac{3}{2}}\Rightarrow du=\dfrac{3}{2}\sqrt{x}\\\displaystyle\int\dfrac{\sqrt{x}}{\sqrt{1-x^3}}dx=\dfrac{2}{3}\int\dfrac{1}{\sqrt{1-u^2}}du=\dfrac{2}{3}\arcsin u+C=\dfrac{2}{3}\arcsin x^{\frac{3}{2}}+C[/tex]