a)
∡C = 180° - (90° + 60°) = 180° - 150° = 30°
Conform T30° => AC = 2AB = 2×10 = 20 cm
Pitagora
BC = √AC² - AB² = √20² - 10² = √400 - 100 = √300 = 10√3 cm
b)
AM = √AB² + BM² = √100 + 100 = √200 = 10√2 cm
(BM = BC/2 = 20/2 = 10 cm)
P = AB + BM + AM = 10 + 10 + 10√2 = 10·(2 + √2) cm