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Determinati numărul de solutii intregi ale ecuației 3x^2 + 8x - 3 = 0.


Răspuns :

[tex](x - 3 ) ( 3 x + 1 ) = 0(X-3)(3X+1)=0

  1. x - 3 ) ( 3 x + 1 ) = 0(X-3)(3X+1)=0 \\ x = 3 \\ x = - \frac{1}{3} \\ 3x + 1 = 0 \\ x = 3 \: si - \frac{1}{3}
  2. (x - 3 ) ( 3 x + 1 ) = 0(X-3)(3X+1)=0 \\ x = 3 \\ x = - \frac{1}{3} \\ 3x + 1 = 0 \\ x = 3 \: si - \frac{1}{3} [/tex]
  3. Succes:))

a=3, b=8, c=-3

Δ=b²-4ac=8²-4*3*(-3)=64+36=100

x1=(-b+√Δ)/2a=(-8+10)/(2*3)=2/(2*3)=1/3

x2=(-b-√Δ)/2a=(-8-10)/(2*3)=-18/(2*3)=-18/6=-3∈Z

S={-3}