Răspuns:
yAB= -0.25x-2.75
yBC= -0.167x-3.167
yCA= -0.5x-3.5
Ha (modul)=I((-0.167)*5-(-4)+(-3.167))/(1+0.167^2)^0.5I=0.657
Hb= 1.789
Hc=0.485
AB= ((5+3)^2+(4-2)^2)^0.5=8.246
Sabc= AB*Hc/2=8.246*.485/2=2.04
Explicație pas cu pas:
ec AB A(-3,-2 ) B(5,-4)
-2=-3*m1+n1
-4=5m1+n1
_________________
-2=8m1 => m1=-0.5 => n1= -2- 3*0.25=-2.75
dist de la un punct (ax,ay) la o dreapta y=mx+n
H = modul [(m*ax-ay+n)/(1+m^2)^0.5]
lungimea AB = ((xb-xa)^2+(yb-ya)^2)^0.5
