Răspuns:
Explicație pas cu pas:
c) primul termen ( x+1)(x+1+x-1/(x+1)(x+2)=(x+1)×2x/(x+1)(x+2)=2x/(x+2)
al doilea termen (x²-2x+1+3x-1)/[2x(x+1)+x+1]=x(x+1)/(x+1)(2x+1)=x/(2x+1)
Am eliminat nedeterminarea: (x+1)
Limx→-1=2(-1)/(-1+2) +(-1)/(-2+1)=-2+1=-1
a) limx→∞(2x+1/3x²+4x+1 - x/x√1+1/x²) =0×1=0