Răspuns:
Explicație:
K I
r.a.=1 : 1
r.m.= 39 : 127
M=39 + 127=166------->166g/moli
Comp.proc. prin masa molara
166g K I------------39g K----------127g Iod
100g------------------------x---------------y
x=100.39 : 166=23,49 % K
y=100.127 :166=76,51 % Iod