Răspuns:
tg=cateta opusa/cateta alaturata
tg(c)=[tex]\frac{AB}{AC}[/tex]
[tex]\frac{AB}{AC} =\frac{4}{3} \\[/tex]
rezulta AB=[tex]\frac{4AC}{3}[/tex]
Aplicam teorema lui pitagora
[tex]BC^{2} =AB^{2} +AC^{2}[/tex]
[tex]BC^{2} =\frac{16AC^{2} }{9} +AC^{2}[/tex]
aducem la acelasi numitor
9*225=25[tex]AC^{2}[/tex]
rezulta AC=9, AB = 12
A=[tex]\frac{C1*C2}{2} =\frac{AB*AC}{2} =\frac{9*12}{2} =54cm^{2}[/tex]
P=AB+AC+BC=12+9+15=36cm
