Răspuns:
Explicație pas cu pas:
[tex]\displaystyle F(-x)=\int_{-x}^{-2x}\dfrac{t^2}{t^2+\sin^2t}dt\\\texttt{Facem scimbarea de variabila }t=-u\Rightarrow dt=-du\\\texttt{Integrala devine:}\\F(-x)=-\int_{x}^{2x}\dfrac{(-u)^2}{(-u)^2+\sin^2(-u)}du=-\int_x^{2x}\dfrac{u^2}{u^2+\sin^2 u}du=-F(x)\\F(-x)=-F(x)\Rightarrow \texttt{functia este impara}[/tex]
