Răspuns:
Explicație pas cu pas:
1)[tex](\sqrt{3}-1)^2 +\frac{4}{\sqrt{12} }+(0,08-0,9):0,3=3-2\sqrt{3}+1+\frac{4\sqrt{12} }{12} +\\ +(\frac{8}{100}-\frac{9}{10})*\frac{10}{3} =4-2\sqrt{3}+\frac{2\sqrt{3} }{3} -\frac{82}{100}*\frac{10}{3}=\frac{120-60\sqrt{3}+20\sqrt{3}-82 }{30} =\\ =\frac{38-40\sqrt{3} }{30}[/tex]
2)x²+7=10
x²=3
x₁=-√3 ;x₂=√3
3)d=16 cm; atunci x²+x²=16;2x²=16;x²=8
A=x²=8 cm²
4)f(x)=-2x+3
f(-10)=20+3=23
