Răspuns:
Explicație pas cu pas:
1. √36-√(-25)²+√(4-6)²+√121=√6²-√25²+√(-2)²+√11²=6-25+√2²+11=-19+2+11=-17+11=-6
2. (√18-√50+3√2)·√2^(-3)=(3√2-5√2+3√2)·√(1/2)³=√2·1/(2√2)=1/2
3. √(n+2)≤3√5<√(n+3) |² ⇔
n+2≤45<n+3 | -45 ⇔
n-43≤0<n-42 ⇒
n-43≤0 si n-42>0 ⇔
n≤43 si n>42 ⇒n=43
4. (n-3)²-n²=n²-6n+9-n²=9-6n
n natural
n : 0 1 ..... ∞
9-6n: 9 3.....-∞ ⇒n=0 atunci se atinge valoarea maxima
