Răspuns:
Explicație pas cu pas:
j)
→ introduc intregii in fractii:
1 intreg si 2/5 = (1×5+2)/5 = 7/5
1 intreg si 1/4 = ( 1×4+1)/4 = 5/4
1 intreg si 3/5 = ( 1×5+3)/5 = 8/5
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= [ (3/5)⁷ : (2 - 7/5)⁴ + 5 : 5/4 - (3/5)³] : 8/5 =
= [ (3/5)⁷ : (10/5 - 7/5)⁴ + 5 x (4/5) - (3/5)³ ] x (5/8) =
= [ (3/5)⁷ : (3/5)⁴ + 5 x (4/5) - (3/5)³ ] x (5/8) =
= [ (3/5)⁽⁷⁻⁴) + 4 - (3/5)³ ] x (5/8) =
= [ (3/5)³ + 4 - (3/5)³] x (5/8) =
(3/5)³ - (3/5)³ = 0
= 4 x (5/8 ) =
= 5/2 =
= 2 intregi si 1/2
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k)
[ ( 1/2 + 2/3 + 5/6) : 12/7 - 6 x (1/18) ] x (1/4) : ( 5 x 12/25 - 4/3) =
= [ (3/6 + 4/6 + 5/6) : 12/7 - 1/3 ] x (1/4) : ( 12/5 - 4/3) =
= [ ( 12/6 ) x ( 7/12) - 1/3] x ( 1/4) : ( 36/15 - 20/15 ) =
= ( 7/6 - 2/6) x ( 1/4) : (16/15) =
= ( 5/6) x (1/4) x (15/16) =
= 75/ 384
