Cm.finala = md/miuxVs.final
miu.HNO3 = 63 g/mol
=> Cm.finala = md/63Vs.fin
Vs.initial = 74,63 mL si ro. p = 1,34 g/ml
stim ca p = ms/Vs
=> ms = pxVs.initiala = 1,34x74,63 = 100 g
stim c% = mdx100/ms
=> md = msxc%/100 = 100x55/100 = 55 g
=> din Cm scoatem pe Vs.fin
=> Vs.fin = md/Cm.finx63
= 55/1x63 = 0,873 L = 873 mL
=> V.apa = Vs.fin - Vs.init
= 873 - 74,63 = 798,37 mL apa
p.apa = 1 g/mL
=> m.apa = 798,37 g
